Editing Pressure, Volume, Quantity, and Temperature
Warning: You are not logged in. Your IP address will be publicly visible if you make any edits. If you log in or create an account, your edits will be attributed to your username, along with other benefits.
The edit can be undone.
Please check the comparison below to verify that this is what you want to do, and then save the changes below to finish undoing the edit.
| Latest revision | Your text | ||
| Line 5: | Line 5: | ||
''Side note: I use engineering notation here sometimes. For example, one thousand can be shown as 1E3. I may also use a 'k' too, but that can sometimes be confused with the K for Kelvins, so I try to stay clear of it.'' | ''Side note: I use engineering notation here sometimes. For example, one thousand can be shown as 1E3. I may also use a 'k' too, but that can sometimes be confused with the K for Kelvins, so I try to stay clear of it.'' | ||
| − | ''Side side note: | + | ''Side side note: I haven't checked these calculations.'' |
== Definitions== | == Definitions== | ||
| Line 15: | Line 15: | ||
'''Quantity''': The number of particles contained in a particular space. In our case, it is the number of molecules measured in '''mol'''es. 1 Mole = 6.022E23 molecules. (or around 602,200,000,000,000,000,000,000 molecules. ). | '''Quantity''': The number of particles contained in a particular space. In our case, it is the number of molecules measured in '''mol'''es. 1 Mole = 6.022E23 molecules. (or around 602,200,000,000,000,000,000,000 molecules. ). | ||
| − | '''Temperature''': A measure of the thermal energy of the gas. Once measured in Fahrenheit (in the dark times), now measured in degrees Celsius or Kelvin. To convert from Celsius to Kelvin, simply | + | '''Temperature''': A measure of the thermal energy of the gas. Once measured in Fahrenheit (in the dark times), now measured in degrees Celsius or degrees Kelvin. To convert from Celsius to Kelvin, simply subtract 273.15 degrees. It is impossible to have a negative value on the Kelvin scale. |
== Relating them all together == | == Relating them all together == | ||
| − | All four of the above values balance each other in any given system. A change in one will effect the others. | + | All four of the above values balance each other in any given system. A change in one will effect the others. |
| − | |||
| − | |||
| − | |||
| − | |||
| − | |||
| − | |||
=== For example=== | === For example=== | ||
| Line 45: | Line 39: | ||
* T - Temperature in Kelvin | * T - Temperature in Kelvin | ||
* R - Ideal Gas Constant (in this case, we use 8314.46261815324) in unites of (deep breath..) Liter Pascals per Kelvin moles (Lit * Pa)/(mol * deg K) | * R - Ideal Gas Constant (in this case, we use 8314.46261815324) in unites of (deep breath..) Liter Pascals per Kelvin moles (Lit * Pa)/(mol * deg K) | ||
| − | |||
| − | |||
So, if we had a furnace with 2 mol of gas in it at 300 degrees Kelvin, what would be the pressure? (A furnace has a 1,000 liter capacity) | So, if we had a furnace with 2 mol of gas in it at 300 degrees Kelvin, what would be the pressure? (A furnace has a 1,000 liter capacity) | ||
| Line 58: | Line 50: | ||
== Volume Pump Example== | == Volume Pump Example== | ||
| − | + | ||
| − | Using the same conditions as above, assume there is a volume pump attached to the input (like you find on an advanced furnace. If you're poor and can't afford an advanced furnace, use a regular furnace with an attached volume pump on the inlet. You hobo). Assume the pressure behind the volume pump is at a steady 50 Megapascals (50E6 Pascals) at 200 Kelvin and there is 5 pipe segments (100 Liters per pipe segment = 500 Liters). The stationer (being dumb, I guess) turns the pump up to 100 Liters. How much pressure is going to be added to the system on each game tick? Should the stationeer be sh***ing their space suit? | + | Using the same conditions as above, assume there is a volume pump attached to the input (like you find on an advanced furnace. If you're poor and can't afford an advanced furnace, use a regular furnace with an attached volume pump on the inlet. You hobo). Assume the pressure behind the volume pump is at a steady 50 Megapascals (50E6 Pascals) at 200 degrees Kelvin and there is 5 pipe segments (100 Liters per pipe segment = 500 Liters). The stationer (being dumb, I guess) turns the pump up to 100 Liters. How much pressure is going to be added to the system on each game tick? Should the stationeer be sh***ing their space suit? |
''Now is a good time to mention that the dial on a volume pump is actually a measure of rate, not volume. When setting the volume pump to 10 Liters, it actually means "10 Liters per game tick". WHY it's just labelled as volume and what determines a game tick? I don't know, go ask the devloper - I'm busy.'' | ''Now is a good time to mention that the dial on a volume pump is actually a measure of rate, not volume. When setting the volume pump to 10 Liters, it actually means "10 Liters per game tick". WHY it's just labelled as volume and what determines a game tick? I don't know, go ask the devloper - I'm busy.'' | ||
| Line 67: | Line 59: | ||
* n = (PV)/(RT) | * n = (PV)/(RT) | ||
* R = 8314.46 (This is always the same.. That's why they call it a 'constant) | * R = 8314.46 (This is always the same.. That's why they call it a 'constant) | ||
| − | * T = 200 Kelvin | + | * T = 200 degrees Kelvin |
* P = 50E6 Pascals | * P = 50E6 Pascals | ||
* V = 500 Liters of pipe (5 segments, each holding 100 Liters) | * V = 500 Liters of pipe (5 segments, each holding 100 Liters) | ||
| Line 98: | Line 90: | ||
'''P = (nRT)/V'''<br> | '''P = (nRT)/V'''<br> | ||
| − | '''dP/dn = (d/dn)(nRT)/V = (RT/V)*(d | + | '''dP/dn = (d/dn)(nRT)/V = (RT/V)*(dn/d)n = RT/V''' (in unites of Pascals per mole) |
Change in temperature with respect to the change in pressure: | Change in temperature with respect to the change in pressure: | ||
'''T = (PV)/(nR)'''<br> | '''T = (PV)/(nR)'''<br> | ||
'''dT/dP = (d/dP){(PV)/(nR)} = {V/(nR)} * (d/dP)P = V/(nR)''' | '''dT/dP = (d/dP){(PV)/(nR)} = {V/(nR)} * (d/dP)P = V/(nR)''' | ||